A 5kVA single-phase transformer has
a turns ratio of 10:1 and is fed from a 2.5kV supply.
Neglecting losses, determine
(a) The full-load secondary current,
(b) The minimum load resistance which can be connected to the secondary winding to give full load kVA,
(c) The primary current at full load kVA.
answer
Since
N1/N=V1/V2 secondary voltage
V2 = V1(N2/N1)= 2500(1/10)=250v
The transformer rating in volt-amperes=V2 i2 (at full load)
i.e. 5000=250I2
Hence full-load secondary current,
i2 = (5000/250) = 20A.
(b) Minimum value of load resistance,
RL =(V2/V1)=(250/20)=12.5Ω
(c) (N1/N2)=(i2/i1) from which primary current
i1 = i2(N1/N2)= 20(1/10)=2A
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